y^2=250

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Solution for y^2=250 equation:



y^2=250
We move all terms to the left:
y^2-(250)=0
a = 1; b = 0; c = -250;
Δ = b2-4ac
Δ = 02-4·1·(-250)
Δ = 1000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{1000}=\sqrt{100*10}=\sqrt{100}*\sqrt{10}=10\sqrt{10}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{10}}{2*1}=\frac{0-10\sqrt{10}}{2} =-\frac{10\sqrt{10}}{2} =-5\sqrt{10} $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{10}}{2*1}=\frac{0+10\sqrt{10}}{2} =\frac{10\sqrt{10}}{2} =5\sqrt{10} $

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